b^2-4b-77=0

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Solution for b^2-4b-77=0 equation:


Simplifying
b2 + -4b + -77 = 0

Reorder the terms:
-77 + -4b + b2 = 0

Solving
-77 + -4b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-7 + -1b)(11 + -1b) = 0

Subproblem 1

Set the factor '(-7 + -1b)' equal to zero and attempt to solve: Simplifying -7 + -1b = 0 Solving -7 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1b = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1b = 0 + 7 -1b = 0 + 7 Combine like terms: 0 + 7 = 7 -1b = 7 Divide each side by '-1'. b = -7 Simplifying b = -7

Subproblem 2

Set the factor '(11 + -1b)' equal to zero and attempt to solve: Simplifying 11 + -1b = 0 Solving 11 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + -1b = 0 + -11 Combine like terms: 11 + -11 = 0 0 + -1b = 0 + -11 -1b = 0 + -11 Combine like terms: 0 + -11 = -11 -1b = -11 Divide each side by '-1'. b = 11 Simplifying b = 11

Solution

b = {-7, 11}

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